Farmer John prides himself on having the healthiest dairy cows in the world. He knows the vitamin content for one scoop of each feed type and the minimum daily vitamin requirement for his cows. Help Farmer John feed the cows so they stay healthy while minimizing the number of scoops that a cow is fed.
Given the daily requirements of each kind of vitamin that a cow needs, identify the smallest combination of scoops of feed a cow can be fed in order to meet at least the minimum vitamin requirements.
Vitamins are measured in integer units. Cows can be fed at most one scoop of any feed type. It is guaranteed that a solution exists for all contest input data.
Line 1: | integer V (1 <= V <= 25), the number of types of vitamins |
---|---|
Line 2: | V integers (1 <= each one <= 1000), the minimum requirement for each of the V vitamins that a cow requires each day |
Line 3: | integer G (1 <= G <= 15), the number of types of feeds available |
Lines 4..G+3: | V integers (0 <= each one <= 1000), the amount of each vitamin that one scoop of this feed contains. The first line of these G lines describes feed #1; the second line describes feed #2; and so on. |
4
100 200 300 400
3
50 50 50 50
200 300 200 300
900 150 389 399
The output is a single line of output that contains:
If more than one set of feedtypes yield a minimum of scoops, choose the set with the smallest feedtype numbers.
2 1 3
public class holstein {
public static void main(String[] args) throws IOException {
try (final BufferedReader f = new BufferedReader(new FileReader("holstein.in"));
final PrintWriter out = new PrintWriter(new BufferedWriter(new FileWriter("holstein.out")))) {
// number of types of vitamins
final int V = Integer.parseInt(f.readLine());
// minimum requirement for each vitamin
final int[] minimum = new int[V];
final String[] tokens = f.readLine().split(" ");
for (int i = 0; i < V; i++) {
minimum[i] = Integer.parseInt(tokens[i]);
}
// number of types of feeds
final int G = Integer.parseInt(f.readLine());
// amount of each vitamin found in one scoop of each feed
final int[][] feeds = new int[G][V];
for (int g = 0; g < G; g++) {
final Scanner scanner = new Scanner(f.readLine());
for (int v = 0; v < V; v++) {
feeds[g][v] = scanner.nextInt();
}
scanner.close();
}
// find solution
final Set<Integer> seen = new HashSet<>();
final List<Result> results = new ArrayList<>();
for (int i = 0; i < G; i++) {
final int[] scoops = new int[G];
final int[] amounts = new int[V];
addScoop(i, scoops, amounts, feeds);
findScoops(scoops, amounts, minimum, feeds, G, seen, results);
}
// output result
final Result bestResult = results.get(results.size() - 1);
out.print(bestResult.scoopCount);
for (int i = 0; i < bestResult.scoops.length; i++) {
if (bestResult.scoops[i] == 1) {
out.print(" " + (i + 1));
}
}
out.println();
}
}
private static boolean findScoops(int[] scoops, int[] amounts, int[] minimum,
int[][] feeds, int feedCount,
Set<Integer> seen, List<Result> results) {
if (isMeetsMinimum(amounts, minimum)) {
final Result result = new Result(scoops, amounts);
results.add(result);
return true; // found a solution
}
// optimization: try adding another scoop, but only if we don't
// already have an answer with fewer scoops
int scoopCount = getScoopCount(scoops);
int minimumScoopCount = getMinimumScoopCount(results);
if ((minimumScoopCount > 0) && (scoopCount == minimumScoopCount)) {
return true; // already found a better solution previously
}
for (int i = 0; i < feedCount; i++) {
final int[] newScoops = Arrays.copyOf(scoops, scoops.length);
final int[] newAmounts = Arrays.copyOf(amounts, amounts.length);
if (newScoops[i] != 1) {
addScoop(i, newScoops, newAmounts, feeds);
// optimization: make sure we didn't already compute this combination before
final int newScoopKey = scoopsToKey(newScoops);
if (!seen.contains(newScoopKey)) {
seen.add(newScoopKey);
// check if the new scoop combo is a solution
if (findScoops(newScoops, newAmounts, minimum, feeds, feedCount, seen, results)) {
// found solution; no need to try next combo in this loop
break;
}
}
}
}
return false; // keep looking for a solution
}
private static void addScoop(int index, int[] scoops, int[] amounts, int[][] feeds) {
scoops[index] = 1;
for (int i = 0; i < amounts.length; i++) {
amounts[i] += feeds[index][i];
}
}
private static boolean isMeetsMinimum(int[] amounts, int[] minimum) {
for (int i = 0; i < amounts.length; i++) {
if (amounts[i] < minimum[i]) {
return false;
}
}
return true;
}
private static int getScoopCount(int[] scoops) {
int scoopCount = 0;
for (int scoop : scoops) {
if (scoop == 1) {
scoopCount++;
}
}
return scoopCount;
}
private static int getMinimumScoopCount(List<Result> results) {
if (results.isEmpty()) {
return 0;
}
Result bestResult = results.get(results.size() - 1);
return bestResult.scoopCount;
}
private static int scoopsToKey(int[] scoops) {
int key = 0;
for (int i = 0; i < scoops.length; i++) {
if (scoops[i] == 1) {
key = key | (1 << i);
}
}
return key;
}
static class Result {
int[] scoops;
int[] amount;
int scoopCount;
private Result() {
super();
}
Result(int[] scoops, int[] amount) {
this();
this.scoops = scoops;
this.amount = amount;
for (int scoop : scoops) {
if (scoop == 1) {
scoopCount++;
}
}
}
@Override
public boolean equals(Object obj) {
if (obj == null) {
return false;
}
if (!Result.class.isAssignableFrom(obj.getClass())) {
return false;
}
final Result other = (Result) obj;
return Arrays.equals(this.scoops, other.scoops);
}
@Override
public int hashCode() {
int hash = 3;
for (int scoop : scoops) {
hash = 53 * hash + scoop;
}
return hash;
}
}
}
Link To: Java Source Code